2j^2+29j-15=0

Solution for 2j^2+29j-15=0 equation:

Simplifying
2j2 + 29j + -15 = 0

Reorder the terms:
-15 + 29j + 2j2 = 0

Solving
-15 + 29j + 2j2 = 0

Solving for variable 'j'.

Factor a trinomial.
(-15 + -1j)(1 + -2j) = 0

Subproblem 1
Set the factor '(-15 + -1j)' equal to zero and attempt to solve:

Simplifying
-15 + -1j = 0

Solving
-15 + -1j = 0

Move all terms containing j to the left, all other terms to the right.

Add '15' to each side of the equation.
-15 + 15 + -1j = 0 + 15

Combine like terms: -15 + 15 = 0
0 + -1j = 0 + 15
-1j = 0 + 15

Combine like terms: 0 + 15 = 15
-1j = 15

Divide each side by '-1'.
j = -15

Simplifying
j = -15
Subproblem 2
Set the factor '(1 + -2j)' equal to zero and attempt to solve:

Simplifying
1 + -2j = 0

Solving
1 + -2j = 0

Move all terms containing j to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -2j = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -2j = 0 + -1
-2j = 0 + -1

Combine like terms: 0 + -1 = -1
-2j = -1

Divide each side by '-2'.
j = 0.5

Simplifying
j = 0.5
Solution
j = {-15, 0.5}